Two simple harmonic motion y_(1)=A sin omega t and y_(2)=A cos omegat are sxuperimposed on a particle of mass m. Find the total mechanical energy of the particle.

Two simple harmonic motion y_(1)=A sin omega t and y_(2)=A cos omegat

1.	Two simple harmonic motion y_(1)=A sin omega t and y_(2)=A cos omegat are sxuperimposed on a particle of mass m. Find the total mechanical energy of the particle.
Answer» Solution :Phase difference between the two SHM is `90^(@)` Therefore RESULTANT amplitude is `A=sqrt(2a)E=1/2m OMEGA^(2)A_(R)^(2)` `=1/2momega^(2)(sqrt(2)A)^(2)=m omega^(2)A^(2)`