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Two simple harmonic motions are represented by `y_(1)=5 [sin 2 pi t + sqrt(3)cos 2 pi t] and y_(2) = 5 sin (2pit+(pi)/(4))` The ratio of their amplitudes isA. `1 : 1`B. `2 : 1`C. `1 : 3`D. `sqrt(3) : 1` |
Answer» Correct Answer - B `y_(1)=5[sin2pit+sqrt(3)cos 2pit]` `= 10((1)/(2)sin 2 pi + (sqrt(3))/(2)cos 2 pi t)` `=10("cos"(pi)/(3)sin 2 pi t + "sin"(pi)/(3)cos 2 pi t)` `=10[(sin 2 pi t + (pi)/(3))]rArr A_(1)=10` Similarly, `y_(2)=5sin(2pit+(pi)/(4))rArr A_(2)=5` Hence, `(A_(1))/(A_(2))=(10)/(5)=(2)/(1)` |
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