1.

Two simple harmonic motions of angular frequency 100 and 1000 rad s^(-1) have the same displacement amplitude. The ratio of their maximum acceleration is………

Answer»

`1 : 10`
`1 : 10^(2)`
`1 : 10^(3)`
`1 : 10^(4)`

SOLUTION :In `a_("MAX")= OMEGA^(2)A`, A is equal
`therefore a_("max") propto omega^(2)`
`therefore ((a_("max"))_1)/((a_("max"))_2) = ((omega_1)/(omega_2))^(2)= ((100)/(1000))^(2)= (1)/(100)`.


Discussion

No Comment Found