Two simple harmonic motions y_(1) =A sinomegat and y_(2) =A cos omegat are superimposed on a particle of mass m. Find the total mechanical energy of the particle.

Two simple harmonic motions y_(1) =A sinomegat and y_(2) =A cos omegat

1.	Two simple harmonic motions y_(1) =A sinomegat and y_(2) =A cos omegat are superimposed on a particle of mass m. Find the total mechanical energy of the particle.
Answer» Solution :Phase difference between the TWO SHMS is `90^(@)` THEREFORE, resultant amplitude is `A= sqrt(2A)E= (1)/(2)momega^(2)A_(R)^(2)= (1)/(2)momega^(2)(sqrt(2)A)^(2)= momega^(2)A^(2)`