InterviewSolution
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InterviewSolution
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Two simple pendulum first of bob mass `M_(1)` and length `L_(1)` second of bob mass `M_(2)` and length `L_(2) M_(1) = M_(2)` and `L_(1)` = 2L_(2)`. if the vibrational energy of both is same which is correct?A. Amplitude of B greater than AB. Amplitude of B smaller than AC. Amplitude will be sameD. None of the above |
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Answer» Correct Answer - B Frequency, `n = (1)/(2pi)sqrt((g)/(l)) or n prop (1)/(sqrt(l))` `therefore" "(n_(1))/(n_(2))= sqrt((l_(2))/(l_(1)))=sqrt((L_(2))/(2L_(2)))=(1)/(sqrt(2))=n_(2)=sqrt(2) n_(1)` `rArr" "n_(2) gt n_(1)` Energy, `E = (1)/(2)m omega^(2)a^(2)=2pi^(2)mn^(2)a^(2)` and `a^(2)prop (1)/(mn^(2))rArr (a_(1)^(2))/(a_(2)^(2))=(m_(2)n_(2)^(2))/(m_(1)n_(1)^(2))" "(because "E is same")` Given, `n_(2) gt n_(1) and m_(1) = m_(2)` `rArr" "a_(1) gt a_(2)`. So, amplitude of B smaller than A. |
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