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Two simple pendulums have lengths in the ratio 1 : 9. What is the ratio of their periods at a given place ? |
Answer» T = 2\(\pi\) \(\sqrt{\frac Lg}\) \(\therefore\) \(\frac{T_2}{T_1}\) = \(\sqrt{\frac {L_2}{L_1}}\) = √9 = 3 \(\therefore\) T1 : T2 = 1 : 3 |
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