Two soap bubble of radii `R_(1)` and `R_(2)` are in atmosphere of pressure `P_(0)` at constant temperature. Ratio of masses of air inside them is

Two soap bubble of radii `R_(1)` and `R_(2)` are in atmosphere of pres

1.	Two soap bubble of radii `R_(1)` and `R_(2)` are in atmosphere of pressure `P_(0)` at constant temperature. Ratio of masses of air inside them is
Answer» `PV=(m)/(M)Rti.e.,mpropPV(m_(1))/(m_(2))=(P_(1)V_(1))/(P_(2)V_(2))` `p_(1)=p_(0)+(4T)/(R_(1)),p_(2)=p_(0)+(4T)/(R_(2))` `=((P_(0)+(4T)/(R_(1)))(4)/(3)piR_(1)^(3))/((P_(0)+(4T)/(R_(2)))(4)/(3)piR_(2)^(3))=((P_(0)+(4T)/(R_(1)))R_(1)^(3))/((P_(0)+(4T)/(R_(2)))R_(2)^(3))`

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Two soap bubble of radii `R_(1)` and `R_(2)` are in atmosphere of pressure `P_(0)` at constant temperature. Ratio of masses of air inside them is

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