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Two solids spheres made of same metal have weights 11840 grams and 1480 grams . Find the radius of smaller sphere , if diameter of larger sphere is 10 centimetres |
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Answer» Weight of the heavier sphere = 11840 g and weight of the lighter sphere = 1480 g, and diameter of lighter sphere = 10 cm or radius = 5 cmLet the volume of the heavier sphere be 'V1' and the volume of the lighter sphere be 'V2'. Radius of the heavier sphere be 'r1' because the diameter of the lighter sphere is given so the radius is 5cm.Weight of an object = density× volume of that objectSo,(Weight of the heavier sphere/weight of the lighter sphere) = (Density× V1/density× V2)As both the spheres are As both the spheres are made up of same metal, therefore, the ratio of their weights will be equal to the ratio oftheir volumes.(weight of the heavier sphere/weight of the lighter sphere) = (V1/V2)⇒ (11840/1480) = (4/3πr₁³)/(4/3πr³)⇒ (11840/1480) = (4/3×22/7×r₁³)/(4/3× 22/7× 5× 5× 5) |
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