Two sound sources are moving in opposite directions with velocities `v_1` and `v_2(v_1gtv_2)`. Both are moving away from a stationary observer. The frequency of both the sources is 900 Hz. What is the value of `v_1-v_2` so that the beat frequency observed by the observer is 6 Hz? Speed of sound `v=300(m)/(s)`. Given that `v_1` and `v_2ltltltv`.A. `1(m)/(s)`B. `2(m)/(s)`C. `3(m)/(s)`D. `4(m)/(s)`

Two sound sources are moving in opposite directions with velocities `v

1.	Two sound sources are moving in opposite directions with velocities `v_1` and `v_2(v_1gtv_2)`. Both are moving away from a stationary observer. The frequency of both the sources is 900 Hz. What is the value of `v_1-v_2` so that the beat frequency observed by the observer is 6 Hz? Speed of sound `v=300(m)/(s)`. Given that `v_1` and `v_2ltltltv`.A. `1(m)/(s)`B. `2(m)/(s)`C. `3(m)/(s)`D. `4(m)/(s)`
Answer» Correct Answer - B `f_1=900((300)/(300+v_1))` `cong900(1+(v_1)/(300))^-1` `=900-3v_1` similarly, `f_2=900((300)/(300+v_2))=900-3v_s` `f_2-f_1=6` `3(v_1-v_2)=6` `3(v_1-v_2)=6` or `v_1-v_2=2(m)/(s)`

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