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Two sparingly soluble salts AB and XY_(2) have the same solubility product. Which salt will be more soluble ? Explain . |
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Answer» Solution :SUPPOSE SOLUBILITY of `AB = a "MOL " L^(-1) `. Then `AB hArr A^(+) + B^(-) , K_(sp)= [A^(+)][B^(-)]=axxa=a^(2)` `:.a=sqrt(K_(sp))` Suppose solubility of salt `XY_(2) = b "mol" L^(-1)`. Then `XY_(2) hArr X^(2)+2, Y^(-), K_(sp)=[X^(2+)][Y^(-)]^(2)=b(2b)^(2) i.e., 4b^(3)=K_(sp) or b= (K_(sp)//4)^(1//3)` |
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