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Two sparnigly soluble salts AX and BX_(2) have their solubility product constant equal . Which of the following is (are) correct deduction(s) ? |
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Answer» Solubility of `AX` ISW greater than solubility of `BX_(2)`. `K_(sp) = (BX)_(2) = 4S_(2)^(3)` If `S_(1)^(2) = 4S_(2)^(3)`, then `S_(1) = sqrt(4S_(2)^(3)) = 2(S_(2))^(3//2)` `S_(1) gt S_(2)` |
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