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Two sparnigly soluble salts `AX` and `BX_(2)` have their solubility product constant equal . Which of the following is (are) correct deduction(s) ?A. Solubility of `AX` isw greater than solubility of `BX_(2)`.B. If `S_(1)` and `S_(2)` are molar solubility of `AX` and `BX_(2)` then `S_(1) = (S_(2))^(3//2)`C. If X is a conjugate base of a weak acid, addition of `HNO_(3)` will increase solubility of both AX with `BX_(2)`.D. Increasing the temperature, increase the solublity of both `AX` and `BX_(2)`. |
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Answer» Correct Answer - A::C `K_(sp) = (AX) = S_(1)^(2)` `K_(sp) = (BX)_(2) = 4S_(2)^(3)` If `S_(1)^(2) = 4S_(2)^(3)`, then `S_(1) = sqrt(4S_(2)^(3)) = 2(S_(2))^(3//2)` `S_(1) gt S_(2)` |
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