1.

Two springs A and B, having force constant KA and KB (KA = 3KB) are stretched by applying equal forces. If energy stored in A is E, then that in B is1)E/32)E3)3E4)9E

Answer» Two springs A and B, having force constant KA and KB (KA = 3KB) are stretched by applying equal forces. If energy stored in A is E, then that in B is


1)E/3


2)E


3)3E


4)9E


Discussion

No Comment Found

Related InterviewSolutions