InterviewSolution
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InterviewSolution
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Two springs are made to oscillate simple harmonically due to the same mass individually. The time periods obtained are `T_1` and `T_2`. If both the springs are connected in series and hten made to oscillate by the same mass, the resulting time period will beA. `T_1+T_2`B. `(T_1T_2)/(T_1+T_2)`C. `sqrt(T_1^2+T_2^2)`D. `(T_1+T_2)/(2)` |
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Answer» Correct Answer - C Let spring constant of two spring are `k_1` and `k_2` respectively then `T_1=2pisqrt((m)/(k_1))` and `T_2=2pisqrt((m)/(k_2))` `k_1=(4pi^2m)/(T_1^2)` and `k_2=(4pi^2m)/(T_2^2)` When the two springs are connected in series then `T=2pisqrt((m)/(k_(eq)))` where `k_(eq)=(k_1k_2)/(k_1+k_2)` `T=sqrt(T_1^2+T_2^2)` |
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