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Two springs of constants `k_1` and `k_2` have equal maximum velocities, when executing simple harmonic motion. The ratio of their amplitudes (masses are equal) will beA. `(k_(1))/(k_(2))`B. `(k_(2))/(k_(1))`C. `((k_(1))/(k_(2)))^(1//2)`D. `((k_(2))/(k_(1)))^(1//2)` |
Answer» Correct Answer - D `v_(1)=v_(2)` `A_(1)omega_(1)=A_(2)omega_(2)` `(A_(1))/(A_(2))=(omega_(2))/(omega_(1))=(T_(1))/(T_(2))=sqrt((k_(2))/(k_(1)))` |
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