1.

Two square pyramids have the same volume. The base edge of one is half that of the other. How many times the height of the second pyramid is the height of the first?

Answer»

v1 = v2

\(\frac{1}{3}a^2_1h_1\) = \(\frac{1}{3}a^2_2h_2,\) \(\frac{1}{3}a^2h_1\) = \(\frac{1}{3}(\frac{a}{2})^2h_2\)

\(\frac{1}{3}a^2h_1=\frac{1}{3}\times\frac{a^2}{4}\times h_2\)

\(h_1=\frac{h_2}{4},\) 4h1 = h2

The height of the second pyramid is 4 times the height of the first pyramid.



Discussion

No Comment Found

Related InterviewSolutions