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Two straight lines 3x+4y=5 and 4x−3y=15 intersect at point A. Two points B and C are chosen on these lines such that AB=AC. If the two possible equations of BC passing through (1,2) are a1x+b1y+13=0 and a2x+b2y+9=0, then the value of a2b1−a1b2 is equal to |
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Answer» Two straight lines 3x+4y=5 and 4x−3y=15 intersect at point A. Two points B and C are chosen on these lines such that AB=AC. If the two possible equations of BC passing through (1,2) are a1x+b1y+13=0 and a2x+b2y+9=0, then the value of a2b1−a1b2 is equal to |
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