InterviewSolution
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InterviewSolution
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Two straight long conductors AOB and COD are perpendicular to each other and carry currents `I_1` and `I_2`. Find the magnitude of magnetic field induction at a point P at a distance a from the point O in a direction perpendicular to the plane ABCD |
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Answer» Correct Answer - `(mu_0)/(2pia)(I_1^2+I_2^2)^(1//2)` Magnetic field induction at P due to current through AOB and COD will be `B_1=(mu_0)/(4pi)(2I_1)/(a)` and `B_2=(mu_0)/(4pi)(2I_2)/(a)` Here `vecB_1` and `vecB_2` are perpendicular to each other. The magnitude of resultant magnetic field induction will be `B=sqrt(B_1^2+B_2^2)=[((mu_0)/(4pi)(2I_1)/(a))^2+((mu_0)/(4pi)(2I_2)/(a))^2]^(1//2)` `=(mu_0)/(2pia)(I_1^2+I_2^2)^(1//2)` |
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