InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
Two substances of densities `rho_(1)` and `rho_(2)` are mixed in equal volume and the relative density of mixture is `4`. When they are mixed in equal masses, the relative density of the mixture is 3. the values of `rho_(1)` and `rho_(2)` are:A. `rho_(1)=6` and `rho_(2)=2`B. `rho_(1)=3` and `rho_(2)=5`C. `rho_(1)=12` and `rho_(2)=4`D. None of these |
|
Answer» Correct Answer - A When substances are mixed in equal volume then density `=(rho_(1)+rho_(2))/(2)=4 implies rho_(1)+rho_(2) = 8 " "…..(i)` When substance are mixed in equal masses then density `=(2rho_(1)rho_(2))/(rho_(1)+rho_(2)) = 3 implies 2rho_(1)rho_(2) = 3(rho_(1)+rho_(2))" "……(ii)` By solving (i) and (ii) we get `rho_(1) =6` and `rho_(2) =2`. |
|