Two thin wire rings each having radius R are placed at distance d apart with their axes coinciding. The charges on the two are `+Q` and `-Q`. The potential difference between the centre so the two rings isA. `(Q.R)/(4piepsilon_(0)d^(2))`B. `(Q.R)/(2piepsilon_(0))((1)/(R)-(1)/(sqrt(R^(2)+d^(2))))`C. `(Q.R)/(4piepsilon_(0))((1)/(R)-(1)/(sqrt(R^(2)+d^(2))))`D. `0`

Two thin wire rings each having radius R are placed at distance d apar

1.	Two thin wire rings each having radius R are placed at distance d apart with their axes coinciding. The charges on the two are `+Q` and `-Q`. The potential difference between the centre so the two rings isA. `(Q.R)/(4piepsilon_(0)d^(2))`B. `(Q.R)/(2piepsilon_(0))((1)/(R)-(1)/(sqrt(R^(2)+d^(2))))`C. `(Q.R)/(4piepsilon_(0))((1)/(R)-(1)/(sqrt(R^(2)+d^(2))))`D. `0`
Answer» Correct Answer - 2 `E=(1)/(4piepsilon_(0))(qsinpi//2)/(r^(2)pi//2)` `E=(qsin pi//2)/(2pi^(2) epsilon _(0) r^(2)) (-overline(j))`

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