Two – third of a number P is equal to the four – seventh of anothe

1.	Two – third of a number P is equal to the four – seventh of another number Q. R is nine – fourteenth of Q. If difference of P and R is 12, then find the two – seventh of sum of P, Q and R.1. 402. 423. 444. 46
Answer» Correct Answer - Option 1 : 40 GIVEN: Two – third of a number P is equal to the four – seventh of another number Q. R is nine – fourteenth of Q. Difference of P and R is 12. CALCULATION: Two – third of a number P is equal to the two – seventh of another number Q. R is three – fourth of P 2P/3 = 4Q/7 7P = 6Q P : Q = 6 : 7 R = 9Q/14 Q : R = 14 : 9 P : Q : R = (6 × 14) : (7 × 14) : (7 : 9) = 12 : 14 : 9 Let P = 12k, Q = 14k and R = 9k 12k – 9k = 12 k = 4 Now, = (2/7) × (12k + 14k + 9k) = (2/7) × 140 = 40

Two – third of a number P is equal to the four – seventh of another number Q. R is nine – fourteenth of Q. If difference of P and R is 12, then find the two – seventh of sum of P, Q and R.1. 402. 423. 444. 46

Answer» Correct Answer - Option 1 : 40

GIVEN:

Two – third of a number P is equal to the four – seventh of another number Q.

R is nine – fourteenth of Q.

Difference of P and R is 12.

CALCULATION:

Two – third of a number P is equal to the two – seventh of another number Q. R is three – fourth of P

2P/3 = 4Q/7

7P = 6Q

P : Q = 6 : 7

R = 9Q/14

Q : R = 14 : 9

P : Q : R = (6 × 14) : (7 × 14) : (7 : 9) = 12 : 14 : 9

Let P = 12k, Q = 14k and R = 9k

12k – 9k = 12

k = 4

Now,

= (2/7) × (12k + 14k + 9k)

= (2/7) × 140

= 40

Discussion

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