1.

Two this slabs ................

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SOLUTION :
From the given vectors for the direction of LIGHT RAYS we can use For the first medium `SIN theta_(1)=a/SQRT(a^(2)+b^(2))`
and for the second medium `sin theta_(2)= c/sqrt(c^(2)+d^(2))`
By snell's law, we have `mu_(1) sin theta_(1) = mu_(2) sin theta_(2)`
`implies (mu_(1) a)/sqrt(a^(2)+b^(2))=(mu_(2) c)/sqrt(c^(2)+d^(2))`.


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