Saved Bookmarks
| 1. |
Two trains A and B are moving on two parallel tracks with uniform speed of 20ms-1 in the same direction with A ahead of B. The driver of B decides to overtake A and accelerates by 1 ms-2. After 50 seconds, they are moving together, find the original distance of separation. |
|
Answer» Initially, both A and B are moving with the same velocity in the same direction, ∴ The initial relative velocity . uAB = uA – uB = 0 when t = 50 s, relative acceleration = aAB = 1 ms-2 If s is the distance moved, then From s = ut + 1/2at2 S = uAB × t + 1/2 aABt2 S = 0 × t + 1/2 × 1 × 502 = 2500/2 = 1250 m. Hence, the Initial distance of separation is 1250m. |
|