1.

Two trains A and B are moving on two parallel tracks with uniform speed of 20ms-1 in the same direction with A ahead of B. The driver of B decides to overtake A and accelerates by 1 ms-2. After 50 seconds, they are moving together, find the original distance of separation. 

Answer»

Initially, both A and B are moving with the same velocity in the same direction,

∴ The initial relative velocity .

uAB = uA – uB = 0

when t = 50 s,

relative acceleration = aAB = 1 ms-2

If s is the distance moved, then

From s = ut + 1/2at2

S = uAB × t + 1/2 aABt2

S = 0 × t + 1/2 × 1 × 502

= 2500/2 = 1250 m.

Hence, the Initial distance of separation is 1250m.



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