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Two trains A and B each of mass m are moving on a longitude of a spherical planet of mass M and radius R with velocity v relative to to planet. Train A & B presses thhe rail track with forces `N_(A)` & `N_(B)` respectively. [`omega` is angular velocity of planet about its vertical axis] ThenA. `N_(A)=N_(B)=(GmM)/(R^(2))-momega^(2)R`B. `N_(A)=(GmM)/(R^(2))-momega^(2)R+(mv^(2))/(R)`C. `N_(B)=(GmM)/(R^(2))-momega^(2)R-(mv^(2))/(R)`D. `N_(B)=(GmM)/(R^(2))+momega^(2)R-(mv^(2))/(R)` |
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Answer» Correct Answer - C `N_(A)=N_(B)=(GmM)/(R^(2))-momega^(2)R-(mv^(2))/(R)` `((GmM)/(R^(2))-momega^(2)R-N_(A)=(mv^(2))/(R))` |
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