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Two transparent slabs have the same thickness as shown in figure. One in made of material A of refractive index 1.5. The other is made of two materilas B and C with thickness in the ratio 1:2. The refractive index of C is 1.6. If a monochromatic parallel beam passing through the slabs has the same number of wavelengths inside both, the refractive index of B is A. 1.1B. 1.2C. 1.3D. 1.4 |
Answer» Correct Answer - c Total number of waves `=((1.5)t)/(lambda)` `("Total number of waves") = (("optical path length")/("wavelength"))` For B and C: Total number of waves `=(n_(0) ((t)/(3)))/(lambda) + (1.6((2t)/(3)))/(lambda)` Equating (i) and (ii), we get `n_(0) = 1.3` |
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