Two unbiased dice are thrown. Find the probability that the total of t

1.	Two unbiased dice are thrown. Find the probability that the total of the numbers on the dice is greater than 10.
Answer» Given: three dice are rolled Formula: P(E) = \(\frac{favourable\,outcomes}{total\,possible\,outcomes}\) so, we have to determine the probability of getting the same number on all the three dice total number of possible outcomes are 6² = 36 therefore n(S)=36 let E be the event of getting same number on all the three dice E= {(5,6) (6,5) (6,6)} n(E)= 3 P(E) = \(\frac{n(E)}{n(S)}\) P(E) = \(\frac{3}{36}\) = \(\frac{1}{12}\)

Two unbiased dice are thrown. Find the probability that the total of the numbers on the dice is greater than 10.

Answer»

Given: three dice are rolled

Formula: P(E) = \(\frac{favourable\,outcomes}{total\,possible\,outcomes}\)

so, we have to determine the probability of getting the same number on all the three dice total number of possible outcomes are 6² = 36

therefore n(S)=36

let E be the event of getting same number on all the three dice

E= {(5,6) (6,5) (6,6)}

n(E)= 3

P(E) = \(\frac{n(E)}{n(S)}\)

P(E) = \(\frac{3}{36}\) = \(\frac{1}{12}\)

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Two unbiased dice are thrown. Find the probability that the total of the numbers on the dice is greater than 10.

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