Two unequal soap bubbles are formed one on each side of a tube closed in the middle by a tap. What happens when the tap is opened to put the two bubbles in communication?A. No air passes in any direction as the pressures are the same on two sides of the tapB. Larger bubble shrinks and smaller bubble increases in size till they bexome equal in sizeC. Smaller bubble gradually collapses and the bigger one increases in sizeD. None of the above

Two unequal soap bubbles are formed one on each side of a tube closed

1.	Two unequal soap bubbles are formed one on each side of a tube closed in the middle by a tap. What happens when the tap is opened to put the two bubbles in communication?A. No air passes in any direction as the pressures are the same on two sides of the tapB. Larger bubble shrinks and smaller bubble increases in size till they bexome equal in sizeC. Smaller bubble gradually collapses and the bigger one increases in sizeD. None of the above
Answer» Correct Answer - C Pressure inside a soap bubble is given by, `P=P_(0)+(4T)/(r)` ltbRgt So, pressure inside a smaller soap bubble will be more and air will flow from smaller drop to bigger drop.

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