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Two vectors of equal magnitude 5 unit have an angle `60^0` between them. Find the magnitude of a the sum of the vectors and b the difference of the vectors. . . |
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Answer» ure shows the construction of the sum ` vecA+vecB` and the differece `vecA-vecB`. `a vecA+vecB` is the sum to `vecA and vecB`. Both have a magnitude of unit nd the angle between them is `60^0`. Thus, the magnitude of the sum is `|vecA+vecB|=sqrt(5^2+5^2+2xx5x5cos60^0)` `=2xx5 cos 30^0=5sqrt 3` unit. b. ` vecA-vecB` is the sum of `vecA and (-vecB)`. As shown in the ure, angle between `vecA and (-vecB)` is `120^0`. The magnitude of both `vecA and (-vecB)` is 5 unit so, `|vecA-vecB|=sqrt95^2+5^2+2x5xx5 cos 120^0)` 1 = 2xx cos6060 = 5 unit`. |
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