Two volatile liquide A and B are mixed in mole ratio 1:3, to form an ideal liquid solution Vapour pressure of pure. A and B are 600 torr and 200 torr. Volume of container for vapour is 76 litre. (R= 1//12" " "litre" " "atm//K//"mole") The minimum number of distillation steps required, so that mole fraction of A become 0.9 in distillate.

Two volatile liquide A and B are mixed in mole ratio 1:3, to form an i

1.	Two volatile liquide A and B are mixed in mole ratio 1:3, to form an ideal liquid solution Vapour pressure of pure. A and B are 600 torr and 200 torr. Volume of container for vapour is 76 litre. (R= 1//12" " "litre" " "atm//K//"mole") The minimum number of distillation steps required, so that mole fraction of A become 0.9 in distillate.
Answer» `1` `2` `3` `4` SOLUTION :`Y_(A_(1)) = 0.5 = X _(A_(2))` `Y_(A_(2)) = 0.5 xx 600 + 0.6 xx 200 = 400` torr `Y_(A_(2)) = (0.5xx600)/(400)= (3)/(4) = X_(A_(2))` ` Y_(A_(3)) = (3)/(4) xx 600 +(1)/(4) xx 200 = 500` torr ` Y_(A_(3))xx 500 = (3)/(4) xx 600 ` `Y_(A_(3)) xx (9)/(10) = X_(A_(4))`