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Two waves are given by `y_(1)=asin(omegat-kx)` and `y_(2)=a cos(omegat-kx)`. The phase difference between the two waves is -A. `pi//4`B. `pi`C. `pi//8`D. `pi//2` |
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Answer» Correct Answer - D `y_(1)=asin(omegat-kx)` and `y_(2)=acos(omegat-kx)=asin(omegat-kx+(pi)/(2))` Hence phase difference between these two is `(pi)/(2)` |
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