InterviewSolution
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Two waves of equal amplitude and frequency interfere each other. The ratio of intensity when the two waves arrive in phase to that when they arrive `90^@` out of phase isA. `2:1`B. `1:1`C. `sqrt(2):1`D. `4:1` |
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Answer» Correct Answer - A For same phase, phas diff =0 `:. I_("max")=I_(2)+I_(2) +sqrt(I_(1)I_(2)) 2 cos (alpha_(1)-alpha_(2))` `I+I+2I=4I " "...(i)` For phae diff. `=90^(@)` `I_("min")=I_(1)I_(2)+sqrt(I_(1)I_(2)) 2 cos 90` `=2I` Thus, `(I_("max"))/(I_("min"))=(4I)/(2I)=(2)/(I) " "...(ii)` |
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