Two waves of wavelength 99cm and 100cm both travelling with the velocity of 396ms^(-1) are made to interfere. Calculate the number of beats produced b then per sec.

Two waves of wavelength 99cm and 100cm both travelling with the veloci

1.	Two waves of wavelength 99cm and 100cm both travelling with the velocity of 396ms^(-1) are made to interfere. Calculate the number of beats produced b then per sec.
Answer» Solution :`lamda_1 = 99 CM = 0.99 cm` `lamda_2 = 100 cm = 1m ` Velocity of SOUND WAVES in a gas is ` v = 396ms^(-1)` Relation between wavelength and velocity `v = lamda f` ` THEREFORE ` Frequency corresponding to ` lamda_1 , f_1 = (v)/(lamda_1) = (396)/(0.99) , f_1 = 400 Hz` Frequency corresponding to `lamda_2 , f_2 =396 Hz` Number of beats PER second ` \|f_1 - f_2\| = 400 -- 396` n = 4 beats per sec