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Two waves with wavelength lamda have phase difference of 60° at the point of superposition. Find path difference between them.

Answer» <html><body><p>`lamda/6`<br/>`lamda/2`<br/>`2lamda`<br/>`lamda/4`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :We have `Delta <a href="https://interviewquestions.tuteehub.com/tag/phi-599602" style="font-weight:bold;" target="_blank" title="Click to know more about PHI">PHI</a> = (<a href="https://interviewquestions.tuteehub.com/tag/2pi-1838601" style="font-weight:bold;" target="_blank" title="Click to know more about 2PI">2PI</a>)/(lamda) (Delta x)` <br/> `<a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a> (<a href="https://interviewquestions.tuteehub.com/tag/pi-600185" style="font-weight:bold;" target="_blank" title="Click to know more about PI">PI</a> )/(3) = (2pi )/( lamda ) (Delta x)` <br/> `therefore Delta x = (lamda )/(6)`</body></html>


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