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Two wedges, each of mass m, are placed next to each other on a flat horizontal floor. A cube of mass M is balanced on the wedges as shown in figure. Assume no frictionbetween the cube and the wedges, but a coefficent of static friction mult1 between the wedges and the floor. What is the largest M that can be balanced as shown without motion of the wedges ? |
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Answer» `(m)/(sqrt(2))` From `FBD` of blcok `2N cos 45^(@)=Mg……(1)` For wedge to REMAIN at rest `N sin 45^(@) lt mu N'……(2)` and `N' =mg+N cos 45^(@) ….(3)` From `1,2, ` and 3 we get `Mle(2mum)/(1-mu)` |
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