1.

Two wedges, each of mass m, are placed next to each other on a flat horizontal floor. A cube of mass M is balanced on the wedges as shown in figure. Assume no frictionbetween the cube and the wedges, but a coefficent of static friction mult1 between the wedges and the floor. What is the largest M that can be balanced as shown without motion of the wedges ?

Answer»

`(m)/(sqrt(2))`
`(mu m)/(sqrt(2))`
`(mu m)/(1-mu)`
`(2 mu m)/(1-mu)`

Solution :The free body DIAGRAMS of all bodies are as shown.

From `FBD` of blcok
`2N cos 45^(@)=Mg……(1)`
For wedge to REMAIN at rest
`N sin 45^(@) lt mu N'……(2)`
and `N' =mg+N cos 45^(@) ….(3)`
From `1,2, ` and 3 we get
`Mle(2mum)/(1-mu)`


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