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Two wire of equal length, one of copper and the other of steel, are strecthed side by side by the same tension. So that they produce the same note, their diameters should bear a ratio.(rho_(Cu)=8.9 gm/cc and rho_("steel")=7.7 gm/cc) |
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Answer» `1.5:1` `l_(Cu)=l_("steel")` `T_("steel")=T_(Cu)` As v is same, `m_("steel ")=m_(Cu)` `impliesrho_("steel")*[(pid_("steel")^(2))/(4)*l]=r_(Cu)*[(pid_(Cu)^(2))/(4)*l]` `(d_("steel"))/(d_(Cu))=sqrt((rho_(Cu))/(rho_("steel")))=sqrt((8.9)/(7.7))=1.07` |
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