Two wires A and B are formed from the same material with same mass. Diameter of wire A is half of diameter of wire B. If the resistance of wire A is `32 Omega`, find the resistance of wire B.

Two wires A and B are formed from the same material with same mass. Di

1.	Two wires A and B are formed from the same material with same mass. Diameter of wire A is half of diameter of wire B. If the resistance of wire A is `32 Omega`, find the resistance of wire B.
Answer» Volume of A = Volume of B, `pi(D_(A)^(2)//4)l_(A) = pi (D_(B)^(2)//4)l_(B) or l_(A)/l_(B) = D_(B)^(2)/D_(A)^(2)=4` Resistance, `R=rhol/A= rho l/((pi D^(2)//4)) or R prop l/D^(2)` `:. R_(B)/R_(A) =l_(B)/l_(A) xx D_(A)^(2)/D_(B)^(2) = 1/4 xx 1/4=1/16` or `R_(B)=R_(A)/16 = 32/16=2 Omega`.

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Two wires A and B are formed from the same material with same mass. Diameter of wire A is half of diameter of wire B. If the resistance of wire A is `32 Omega`, find the resistance of wire B.

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