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Two wires A and B are of the same material. Their lengths are in the ratio 1 : 2 and the diameter are in the ratio 2 : 1. If they are pulled by the same force, then increase in length will be in the ratioA. `2:1`B. `1:8`C. `1:2`D. `8:1` |
Answer» Correct Answer - B `Y=(MgL_(1))/(pi r_(1)^(2)l_(1)) and Y=(MgL_(2))/(pi r_(2)^(2)l_(2))` `(MgL_(1))/(pi r_(1)^(2)l_(1))=(MgL_(2))/(pi r_(2)^(2)l_(2))` `therefore (l_(1))/(l_(2)) =(L_(1))/(L_(2)) (r_(2)^(2))/(r_(1)^(2)) =(1)/(2) xx ((1)^(2))/((2)^(2)) =(1)/(8)` |
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