Two wires A and B, having identical geometrical construction, are stre

1.	Two wires A and B, having identical geometrical construction, are stretched from their natural length by small but equal amount. The Young's modulus of the wires are YA and YB whereas the densities are PA and N. It is given that YA > YB and pA > pB transverse signal started at one end takes a time t1 to reach the other end for A and t2 for B.(a) t1< t1(b) t1 = t2(c) t1 > t2.(d) The information is insufficient to find the relation between t1 and t2
Answer» (d) The information is insufficient to find the relation between t₁ and t₂ EXPLANATION: Since Yₐ > Yᵦ, for equal strain tension Tₐ > Tᵦ. Since ρₐ > ρᵦ, µₐ > µᵦ. Now vₐ = √(Tₐ/µₐ) and vᵦ = √(Tᵦ/µᵦ) →vₐ/vᵦ = √{(Tₐ/Tᵦ)*(µᵦ/µₐ)} The ratio Tₐ/Tᵦ > 1 but µᵦ/µₐ < 1 Hence to know whether vₐ > vᵦ or not, we need to know the exact ratios of Tₐ/Tᵦ and µᵦ/µₐ which is not given here. Therefore the relation between t₁ and t₂ cannot be found out.

Two wires A and B, having identical geometrical construction, are stretched from their natural length by small but equal amount. The Young's modulus of the wires are YA and YB whereas the densities are PA and N. It is given that YA > YB and pA > pB transverse signal started at one end takes a time t1 to reach the other end for A and t2 for B.(a) t1< t1(b) t1 = t2(c) t1 > t2.(d) The information is insufficient to find the relation between t1 and t2

Answer»

(d) The information is insufficient to find the relation between t₁ and t₂

EXPLANATION:

Since Yₐ > Yᵦ, for equal strain tension Tₐ > Tᵦ. Since ρₐ > ρᵦ, µₐ > µᵦ. Now vₐ = √(Tₐ/µₐ) and vᵦ = √(Tᵦ/µᵦ)

→vₐ/vᵦ = √{(Tₐ/Tᵦ)*(µᵦ/µₐ)}

The ratio Tₐ/Tᵦ > 1 but µᵦ/µₐ < 1

Hence to know whether vₐ > vᵦ or not, we need to know the exact ratios of Tₐ/Tᵦ and µᵦ/µₐ which is not given here. Therefore the relation between t₁ and t₂ cannot be found out.

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