Two wires A and B of the same material and having same length, have th

1.	Two wires A and B of the same material and having same length, have their cross-sectional area in the ratio 1:6. What would be the ratio of heat produced in these wires when same voltage is applied across each?
Answer» H = \(\frac{V^2t}{R}\) = V²t x \(\frac{A}{ρl}\); A = area of cross-section ∴ H∝ A Or, \(\frac{H_1}{H_2}\) = \(\frac{A_1}{A_2}\) = \(\frac{1}{6}\)

Two wires A and B of the same material and having same length, have their cross-sectional area in the ratio 1:6. What would be the ratio of heat produced in these wires when same voltage is applied across each?

Answer»

H = \(\frac{V^2t}{R}\)

= V²t x \(\frac{A}{ρl}\);

A = area of cross-section

∴ H∝ A

Or, \(\frac{H_1}{H_2}\) = \(\frac{A_1}{A_2}\) = \(\frac{1}{6}\)

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Two wires A and B of the same material and having same length, have their cross-sectional area in the ratio 1:6. What would be the ratio of heat produced in these wires when same voltage is applied across each?

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