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Two wires are made of the same material and have the same volume. The area of cross sections of the first and the second wires are A and 2A respectively. If the length of the first wire is increased by Delta l on applying a force F, how much force is needed to stretch the second wire by the same amount ? |
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Answer» 2 Length of wire 1 = l, AREA of wire 1 = A Length of wire 2 = `l/2`, Area of wire `2 = 2A` Wire 1 : `Y_1 = (F/A)/((Deltal)/(l)) "" Y_1 = Y_2"Wire" 2 : Y_2 = ((F.)/(A))/((Deltal)/((l//2)))` `F/A XX l/(Delta l) = (F.)/(2A) xx l/(2Delta l)` `F = (F.)/4 implies F. = 4F`. |
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