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Two wires are wrapped over wooden cylinder to form two co-axial loops carrying currents `i_(1)` and `i_(2)`. If `i_(2)=8i_(1)` the value of `x` for `B=0` at the origin `O` is: A. `(sqrt(7)-1)R`B. `sqrt(5) R`C. `sqrt(3) R`D. `sqrt(7) R` |
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Answer» Correct Answer - D `B_(1)=B_(2) implies (mu_(0))/(4pi) (2i_(1)piR^(2))/((R^(2)+R^(2))^(3//2))=(mu_(0))/(4pi) (2i_(2)piR^(2))/((x^(2)+R^(2))^(3//2))` given `i_(2)=8i_(1)` Solve to get `x=sqrt(7)R` |
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