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Two wires of same length and radius are joined end to end and loaded. The Young.s modulii of the materials of the two wires are Y_(1) and Y_(2). If the combination behaves as a single wire them its Young.s modulus is |
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Answer» Solution :`e=e_(1) +e_(2)" but " e=(F(2L))/(AY_(EQ)), e_(1)=(FL)/(AY_(1)), e_(2)=(Fl)/(AY_(2))` `(F(2l))/(AY_(eq))=(Fl)/(AY_(1))+(Fl)/(AY_(2))` `(2)/(Y_(eq))=(1)/(Y_(1))+(1)/(Y_(2)) RARR Y_(eq)=(2Y_(1)Y_(2))/(Y_(1)+Y_(2))` |
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