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Two wires of the same material and length but diameters in the ratio `1:2` are stretched by the same force. The potential energy per unit volume for the two wires when stretched will be of the ratio.A. `1:1`B. `2:1`C. `4:1`D. `16:1` |
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Answer» Correct Answer - D `(r_(1))/(r_(2))=1/2rArr ` PE (per unit volume) `=1/(2Y)(F/A)^(2)` `PE prop 1//A^(2) rArr (PE_(1))/(PE_(2))=(A_(2)^(2))/(A_(1)^(2))=16:1` |
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