Two wires of the same material but of different diameters carry the same current `i`. If the ratio of their diameters is `2:1` , then the corresponding ratio of their mean drift velocities will beA. `4:1`B. `1:1`C. `1:2`D. `1:4`

Two wires of the same material but of different diameters carry the sa

1.	Two wires of the same material but of different diameters carry the same current `i`. If the ratio of their diameters is `2:1` , then the corresponding ratio of their mean drift velocities will beA. `4:1`B. `1:1`C. `1:2`D. `1:4`
Answer» Correct Answer - D Drift velocity `v_(d)=(l)/(nAe)=(lxx4)/(n pi D^(2)e) " " [because A = pi((D)/(2))^(2)]` i.e., `v_(d) prop (1)/(D^(2)) therefore (v_(d_(1)))/(v_(d_(2)))=(D_(2)^(2))/(D_(1)^(2))=((1)/(2))^(2)=(1)/(4)`

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Two wires of the same material but of different diameters carry the same current `i`. If the ratio of their diameters is `2:1` , then the corresponding ratio of their mean drift velocities will beA. `4:1`B. `1:1`C. `1:2`D. `1:4`

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