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Two wooden blocks of masses1kg and 2kg are separated by a certain distance A bullet of mass 50g fired from a gun pierces through the block of mass1 kg and then stopped in the second block After the impact of the bullet both blocks start moving with the same speedCalculate the percentage loss in the initial velocity of the bullet when it is inbetween the two blocks .

Answer» <html><body><p></p>Solution :Here, ` M_(1) = 1 kgM_(2) = 2 kg ` <br/> ` m = 50 g = (50)/(<a href="https://interviewquestions.tuteehub.com/tag/1000-265236" style="font-weight:bold;" target="_blank" title="Click to know more about 1000">1000</a>) kg = (1)/(2) kg ` <br/>Let `upsilon` = initial velocity of the bullet <br/> `upsilon_(1)` = velocity of the bullet after <a href="https://interviewquestions.tuteehub.com/tag/piercing-600330" style="font-weight:bold;" target="_blank" title="Click to know more about PIERCING">PIERCING</a> through the first block <br/> `V` = velocity of eachblock when hit by the bullet <br/> As the bullet penetrates first block as per the <a href="https://interviewquestions.tuteehub.com/tag/principle-1166255" style="font-weight:bold;" target="_blank" title="Click to know more about PRINCIPLE">PRINCIPLE</a> of conservation of linear momentum ` m upsilon = M_(1) V + m upsilon_(1) ` <br/> Again applying the same principlewhen the bullet is <a href="https://interviewquestions.tuteehub.com/tag/embedded-2070053" style="font-weight:bold;" target="_blank" title="Click to know more about EMBEDDED">EMBEDDED</a> in second block : <br/> ` m upsilon_(1) = (M_(2) + m) V ` <br/> ` upsilon_(1) = ((M _(2) + m ))/(m) = ((2 + 0.05))/(0.05) V = 41 V ` <br/> From (i) ` 0.05 upsilon = 1 V + 0.05 upsilon_(1) = V + 0.05 xx 41 V = 3.05 NV ` <br/> ` upsilon = (3.05 V)/(0.05) = 61 V ` <br/> `%` age loss in initial velocity of bullet `= ((upsilon - upsilon_(1) xx 100))/(upsilon) = ((61 V - 41V))/(61V) = (20)/(61) xx 100 = 32.8 % ` <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/PR_XI_V01_C03_S01_394_S01.png" width="80%"/> .</body></html>


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