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Twobodies A and B of masses 5 kg and 10 kg in contact with each other rest on a table against a rigid wall . The coefficient of friction between the bodies and the table is 0.15.A force of 200 N is applied horizontally to A.What are (a) the reaction of the partition (b) the action-reaction forces between A and B ?What happens when the wall is removed? Does the answer to (b) change, when the bodies are in motion? Ignore the difference between mu_s and mu_k

Answer»

Solution :We assume perfect CONTACT between bodies A and B and the rigid partition.In that case, the self-adjusting normal force on B by the partition (REACTION) equals 200 N. There is no IMPENDING motion and no friction.The action-reaction forces between A and B are ALSO 200 N. Whenthe partition is REMOVED, kinetic friction comes into play.
Acceleration of `A+B = [ 200 - (150 xx 0.15 )]//15 = 11.8 ms^(-2)`
Friction on A` = 0.15 xx 50 = 7.5 N`
`200 - 7.5- F_(AB) = 5 xx 11.8`
`F_(AB) = 1.3 xx 10^2 N` , opposite to motion
`F_(BA) = 1.3 xx 10^2 N` , in the direction of motion


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