1.

Twoelectrodes are fitted in conductance cell 1.5 cm apart while the area of cross-section of each electrode is `0.75 cm^(2)`. The cell constant isA. `1.125 cm^(-1)`B. `0.5 cm^(-1)`C. `2.0 cm^(-1)`D. `0.2 cm^(-1)`

Answer» Correct Answer - C
Cell constant (x) `=l/a=1.5/0.75=2 cm^(-1)`


Discussion

No Comment Found

Related InterviewSolutions