Twoidentical wires of equal lengths are stretched in such a way that their simultaneous vibrations produce 6 beats per second. The tension in one of the wires is changed slightly and it is observed that the beat frequency remains the same. How is it possible ?

Twoidentical wires of equal lengths are stretched in such a way that t

1.	Twoidentical wires of equal lengths are stretched in such a way that their simultaneous vibrations produce 6 beats per second. The tension in one of the wires is changed slightly and it is observed that the beat frequency remains the same. How is it possible ?
Answer» Answer :Thefrequency of a stretchedstring is proportionalto the SQUARE root of the tension. If the FUNDAMENTAL frequency in the 1st wire is more than that in the 2ND wire, tension in the 1st wire `(T_(1) ) gt`the tension in the 2nd wire`(T_(2))` . Then , `n_(1) = n_(2) + 6 ` ,where ` n_(1) and n_(2)` arethe fundamentalfrequencies of thetwo wires respectively . Now, the tension `T_(2)` is increased gradually until the fundamental frequency of the 2nd wire CHANGES to `n_(2)^(') = n_(2) + 12` . Under these circumstanes, thefrequencydifference becomes, `n_(2)^(') - n_(1) = (n_(2) + 12) - (n_(2) + 6) = 6 ` This means that 6 beats he heard again PER second .