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InterviewSolution
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Tyre of a bicycle has voulme `2xx10^(-3)m^(3)` Initially the tube is filled to `75%` of its volume by air at atmospheric pressure of `P_(0)=10^(5)N//m^(2)`. When a rider rides the bicycle the area of contact of tyre with road is `A=24xx10^(-5)m^(2)`. The mass of rider with bicycle is 120kg. The number of stokes which delivers, `V=500cm^(3)` volume of air in each stroke required to infalte the tyres is [Take `g=m//s^(2)`]A. 10B. 11C. 20D. 21 |
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Answer» Correct Answer - D The pressure of air in the tube is `P=(mg)/(A)+P_(0)` `P=6xx10^(5)N//m^(2)` Final volume of air in the tube is, `V=2xx10^(-3)m^(3)` The number of moles of air in the tube after pumping is, Initially volume of air in the tube is, `n=(pV)/(RT)` where T is temperature Thes n moles of air has volume `V_(1)` at atmosphere pressure given by `V_(1)=(nRT)/(P_(0))=(6xx10^(5)xx2xx10^(-3))/(10^(5))m^(3)` `=2xx10^(-3)m^(3)` Initially volume of air in the tube is `V_(0)=0.75xx2xx10^(-3)=1.5xx10^(-3)m^(3)` So, volume of air to be pumped is, `V=V_(1)-V_(0)=10.5xx10^(-5)m^(3)` So, number of strokes of pump required is, `n_(0)=(DeltaV)/(V)=(10.5xx10^(-3))/(0.5xx10^(-3))=21` |
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