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`U_(avg)` speed of `O_(2)` at `pi xx 10` bar pressure in a 8 litre container containg 2 moles is -A. `10^(3)` cm/secB. `sqrt10^(3)` m /secC. `10^(3)` m/secD. `sqrt(2 xx 10^(6))` m/sec |
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Answer» Correct Answer - C `U_(avg) = sqrt((8RT)/(pi m))` PV = nRT `(RT)/(m) = (PV)/(w)` `P = 10 xx pi xx 10^(5) pa` `U_(avvg) = sqrt((8PV)/(pi w)) = sqrt((8 xx 10 xx pi 10^(5) xx 8)/(2 xx 32 xx pi)) = 10^(3) m//s` |
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